t (20) ↔ g (7) h (8) ↔ s (19) m (13) ↔ n (14) y (25) ↔ b (2) l (12) ↔ o (15)
Still nonsense. But note llandrwyd — Welsh has ll as a single phoneme, dd as voiced ‘th’, wy as ‘oo-ee’ sound. This suggests the plaintext might be Welsh or pseudo-Welsh . thmyl lbt jyms bwnd llandrwyd mn mydya fayr
Doesn’t reveal plaintext. If we assume a simple substitution cipher where: t (20) ↔ g (7) h (8) ↔
But possible if it’s or a code where each ciphertext word is a common word with vowels replaced: a→a, e→y, i→y sometimes? Actually in media → mydya : m m, e→y, d d, i→y, a a. So ciphertext y = either e or i in plaintext. That’s possible if the cipher just replaces vowels with y randomly or by position. Doesn’t reveal plaintext
lbt = l b t → ‘l b t’ — maybe ‘lab t’? ‘lob t’? Or ‘let’? l e t → l y t? No, l b t → if b=e, then let? No, b would be e? Unlikely.
y → i or e a → unchanged? f → f? r → r. So fayr = f a y r → f a i r = fair. Works. mydya = m y d y a → m e d i a = media. Works perfectly: y→e and y→i? That’s inconsistent unless y maps to both e and i — impossible for simple substitution unless one plaintext letter maps to two ciphertext letters (unlikely).